2t^2+20t+100=0

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Solution for 2t^2+20t+100=0 equation: 



2t^2+20t+100=0

a = 2; b = 20; c = +100;
Δ = b2-4ac
Δ = 202-4·2·100
Δ = -400
Delta is less than zero, so there is no solution for the equation

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